Knew it was dynamic programming pretty fast, but I fumbled the base case setup and had to backtrack.
Start by clarifying the problem constraints (e.g., unlimited coins, positive denominations, possibility of no solution). Then explain that this is a classic dynamic programming problem where you build up the minimum coins for each amount from 0 to target. Finally, discuss the time and space complexity and potential optimizations.
Pro tip: Mention that while greedy works for some coin systems (like US coins), it fails for arbitrary denominations, so DP is the safe general solution. Also, note that you can optimize space to O(target) by using a 1D array.
Ask about constraints: unlimited coins? positive denominations? return -1 if impossible? This shows attention to detail.
Explain that dynamic programming is ideal because it avoids recomputing subproblems and handles arbitrary denominations.
Let dp[i] be the minimum coins to make amount i. Initialize dp[0]=0 and dp[i]=infinity for i>0. For each coin c, update dp[i] = min(dp[i], dp[i-c]+1) for i from c to target.
Time O(target * number of coins), space O(target). Handle cases like target=0, no solution, and large target.
Mention BFS for unweighted graph interpretation, or if denominations are canonical, greedy might work but DP is safer.
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