Recognize that the minimum eating speed can be found using binary search on the answer space from 1 to max(piles). For each candidate speed, simulate the total hours needed and adjust the search range accordingly. This yields an O(n log m) solution, where m is the maximum pile size.
Pro tip: Mention that the problem is a classic application of binary search on the answer, and that the time complexity is optimal. Also, clarify that the simulation uses ceiling division to compute hours per pile.
Restate the problem: find the minimum integer k such that the total hours to eat all piles, where each pile takes ceil(pile/k) hours, is ≤ h.
The possible speeds range from 1 to the maximum pile size. Speeds below 1 are invalid, and speeds above max(piles) don't reduce time further.
While low ≤ high, compute mid, calculate total hours with speed mid, and if total ≤ h, record mid as a candidate and search left; else search right.
For a given speed k, sum ceil(pile/k) for all piles. Use integer arithmetic: (pile + k - 1) // k to avoid floating point.
After binary search, return the smallest k that satisfies the condition.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.