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My gut said 6 because higher numbers feel more dominant somehow, which is completely wrong.
Recognize that the stopping condition (total ≥ 100) introduces a bias: the final roll is more likely to be a small number because it must not overshoot too much, while larger numbers are more likely to appear earlier. Use renewal theory or simulation to show that 1 appears most frequently, and explain the intuition clearly.
Pro tip: Mention that the expected total after n rolls is 3.5n, so around 29 rolls are needed; the last roll is special and skews the distribution. Quantify the effect with a quick simulation or approximation to demonstrate rigor.
Restate the problem: roll a fair six-sided die repeatedly, sum results, stop when total ≥ 100. Ask which number appears more often across all rolls.
Explain that the stopping condition creates a bias: the final roll must be small enough to not overshoot 100 too much, so smaller numbers are more likely to be the last roll.
Argue that the final roll is more likely to be 1 because it can occur when the previous total is 99, while larger numbers require the previous total to be in a narrower range (e.g., 6 requires previous total 94-99).
Note that non-final rolls are uniformly distributed, but the final roll's bias affects the overall frequency. Since there are many rolls (~29), the bias is diluted but still significant.
Conclude that 1 appears most frequently. Optionally, provide a rough estimate or mention simulation to show the magnitude (e.g., 1 appears about 20% more often than 6).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.