Linked list manipulation always feels deceptively simple until you're actually doing it under pressure.
Clarify the interleaving pattern (e.g., first half nodes interleaved with reversed second half) and edge cases. Then outline a three-step solution: find the middle, reverse the second half, and merge the two halves alternately. Analyze time and space complexity, and discuss potential pitfalls.
Pro tip: Mention that you can avoid extra space by modifying the list in-place, and explicitly handle edge cases like empty list, single node, and odd/even lengths. This shows attention to detail and practical coding maturity.
Confirm the exact interleaving pattern and constraints (e.g., in-place, O(1) space). Discuss edge cases: empty list, one node, two nodes, odd/even length.
Use the slow and fast pointer technique to locate the middle node. This splits the list into two halves (first half may be longer for odd lengths).
Reverse the second half of the list in-place using iterative pointer manipulation. This prepares it for interleaving.
Interleave nodes from the first half and the reversed second half by adjusting next pointers. Ensure the last node points to null.
State time complexity O(n) and space O(1). Walk through an example to verify correctness and discuss potential pitfalls.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.