I knew the general idea pretty quickly: find the max in the unsorted portion, flip it to the front, then flip it into its correct position at the end.
Use a selection-sort-like strategy: for each position from the end down to 1, find the maximum element in the unsorted prefix, flip it to the front, then flip it to its correct position. This guarantees at most 2n flips, well within the 10n limit. Return the list of flip sizes (k values) used.
Pro tip: Mention that the algorithm is optimal in the worst case (2n flips) and that you can optimize by skipping flips when the maximum is already at the front or at its correct position, reducing the constant factor.
Clarify that a pancake flip reverses the prefix of length k, and the goal is to sort the array using at most 10n flips. Note that any sequence of flips that sorts the array is acceptable.
Adopt a selection-sort approach: repeatedly place the largest remaining element at the end of the unsorted portion. This leverages the fact that flips can move any element to the front and then to any position.
For each unsorted prefix of size m (from n down to 2), find the index of the maximum element. If it's not already at the end, flip it to the front (k = index+1), then flip the entire prefix (k = m) to move it to the end.
Write code to perform the flips, record each k, and verify the array is sorted. Test with edge cases like already sorted, reverse sorted, and arrays with duplicates.
Explain that the algorithm uses at most 2n flips (O(n) flips) and O(n^2) time for finding the maximum each time. Mention that you can skip unnecessary flips when the maximum is already in place.
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