The encoding tripped me up for a second because it's 1-indexed parents stored at 0-indexed positions, and I kept confusing myself on the offset.
Preprocess the tree by building an adjacency list with children sorted by node value, and compute binary lifting tables for both parent and child jumps. For each query, simulate the moves efficiently using the precomputed tables to jump multiple steps at once, ensuring O(log N) per move.
Pro tip: Clarify the constraints upfront (e.g., number of nodes, queries, and k values) to choose the right preprocessing depth; often, a simpler approach like storing children in sorted order and using binary lifting for parents suffices, but if k-th child queries are frequent, consider a more advanced structure like a persistent segment tree or wavelet tree.
Clarify the input format: parent array, query format (start node and sequence of moves), and constraints on N, Q, and k. Determine if moves are given as strings or integers and if k-th child is 1-indexed.
Build an adjacency list where each node's children are sorted by their node values. Compute depth and parent pointers for each node, and set up binary lifting tables for O(log N) ancestor queries.
For each node, store its sorted children list. To find the k-th child, use binary search or direct indexing if k is small; if k can be large, consider augmenting with a data structure like a Fenwick tree per node or a persistent segment tree over the Euler tour.
For each move, if it's 'go to parent', use binary lifting to jump up one level in O(1) or O(log N). If it's 'go to k-th child', retrieve the k-th child from the sorted list in O(log degree) or O(1) if using an array. Continue until all moves are processed.
Preprocessing takes O(N log N) time and space for binary lifting and sorting children. Each query takes O(M log N) where M is the number of moves, assuming O(log N) per move. Discuss potential optimizations if needed.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.