Clarify the problem constraints (e.g., array contains positive integers, missing element must be positive, array may be empty). Then leverage the sorted property to achieve O(log n) time using binary search, comparing the element at mid with its expected value (mid + offset).
Pro tip: Always discuss edge cases like empty array, no missing element in range, and negative numbers; also mention that if the array is not sorted, a hash set or cyclic sort could be used, but since it's sorted, binary search is optimal.
Ask about the range of integers, whether the array can be empty, if duplicates are allowed, and if the missing element must be positive. Confirm that the array is sorted in ascending order.
For a sorted array of distinct integers starting from some base (e.g., 1), the element at index i should be base + i. The first index where arr[i] != base + i indicates the missing element is base + i.
Use binary search to find the smallest index i such that arr[i] != base + i. If no such index exists, the missing element is base + n (where n is the array length).
Check if the array is empty (return base), if the first element is greater than base (return base), and if all elements match the pattern (return base + n).
State that the time complexity is O(log n) and space is O(1). Walk through a few test cases to verify correctness.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.