I knew ROW_NUMBER() was the move but fumbled the partition clause at first, wrote PARTITION BY user_id instead of PARTITION BY event_date and just stared at it for a second before catching myself.
Start by aggregating event counts per user per date using GROUP BY. Then use a window function like ROW_NUMBER() or RANK() partitioned by date and ordered by count descending to rank users. Finally, filter to top 3 ranks per date and order the output by date and rank.
Pro tip: Clarify tie-breaking rules upfront (e.g., if multiple users have the same count, use ROW_NUMBER for deterministic results or RANK if ties should be included). Also, mention that you'd validate the query on a small sample to ensure correctness.
Confirm the table schema, event types, and whether 'top three' means exactly three users per date or could include ties. Clarify ordering: by event count descending, then by user ID for determinism.
Write a subquery or CTE that groups by date and user ID, counting events. Use COUNT(*) or COUNT(DISTINCT event_id) depending on whether duplicate events should be counted.
Apply a window function (ROW_NUMBER, RANK, or DENSE_RANK) over a partition by date, ordered by event count descending. Choose the function based on tie-handling requirements.
Wrap the ranked result in an outer query and filter where rank <= 3. Ensure the final output includes date, user ID, event count, and rank.
Order by date ascending and rank ascending (or event count descending) to present the top users per date in a clear, readable format.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.