My first instinct was to overcomplicate it with some graph-based grouping approach.
Clarify the problem constraints and edge cases, then propose an efficient algorithm. A good approach is to model the problem as a graph where each number is a node, and edges connect numbers sharing a digit; the answer is the size of the largest connected component. Alternatively, use union-find or BFS/DFS to find the largest group of numbers that are connected through shared digits.
Pro tip: Discuss trade-offs between different approaches (e.g., graph traversal vs. union-find) and mention time/space complexity. Also, consider if the list can be large and if there are memory constraints, as this shows you think about scalability.
Ask clarifying questions: Are the numbers always 2-digit? Can there be duplicates? What should be returned if no two numbers share a digit? Confirm that the count is for a subset where every pair shares at least one digit (i.e., a clique) or if it's a connected component (where numbers may not all share the same digit but are linked through others). The example suggests connected component, but it's ambiguous.
Recognize that this is a graph connectivity problem: each number is a node, and an edge exists if two numbers share a digit. The goal is to find the largest connected component. Alternatively, if the problem requires a clique (all numbers share a common digit), then it's about finding the most frequent digit among all numbers.
For connected components, use union-find (disjoint set) or BFS/DFS. For efficiency, note that each number has only two digits, so you can group numbers by their digits and then union groups that share a digit. If it's a clique, simply count the frequency of each digit and return the maximum count.
Write code for the chosen approach, handling edge cases like empty list, single element, and numbers with repeated digits (e.g., 55). Test with the given example and additional cases to ensure correctness.
State the time and space complexity. For union-find with path compression, it's nearly O(n α(n)) time and O(n) space. If using digit frequency, it's O(n) time and O(1) space (since only 10 digits).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.