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Took me a minute to even parse what the output was supposed to look like.
First, clarify the problem by restating it and confirming edge cases. Then, outline a two-pointer approach to identify the non-palindromic center, and finally, describe how to insert spaces around that center to separate mirrored characters.
Pro tip: Mention that the center can be found by comparing characters from both ends until they differ or meet, and emphasize that the solution should handle both odd and even length palindromes.
Restate the problem in your own words and ask clarifying questions about input format, output format, and edge cases (e.g., empty string, single character, even-length palindromes).
Use two pointers starting at the beginning and end of the string, moving inward while characters match. The center is the substring between the pointers when they stop matching or cross.
Construct the output by placing a space between each mirrored character and the center substring. For example, for 'abcxyba', the center is 'cxy', so the result is 'a b cxy b a'.
Consider cases where the entire string is a palindrome (no non-palindromic center) or where the center is empty (even-length palindrome). Adjust the spacing logic accordingly.
State that the time complexity is O(n) with a single pass to find the center and O(n) to build the output, and space complexity is O(n) for the output string.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.