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DoorDash·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Apr 2026

Summary

DoorDash coding screen for a software engineer role. One algorithmic problem, pretty focused, nothing else to report on the process side.

Questions Asked (1)

Q1

Given two strings of equal length, determine whether you can make them identical using at most 2 character swaps within the first string.

Algorithms & Data Structures
Author's notes

My first instinct was to find all the positions where the two strings differ and then reason about how many swaps it would take to fix them.

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AI HintsAI Generated

Suggested Approach

First, clarify the problem: swaps are within the first string only, and we can use at most 2 swaps. Then, identify mismatched positions between the two strings. If there are 0 mismatches, return true; if there are 2 mismatches, check if swapping the characters at those positions fixes both; if there are 3 or more, check if a single swap can fix two mismatches and then another swap fixes the rest, or if two swaps can resolve all mismatches. Finally, return true if the mismatches can be resolved with at most 2 swaps, else false.

Pro tip: Always consider edge cases like strings already equal, exactly two mismatches, and more than two mismatches where a swap might fix two at once. Also, discuss time and space complexity: O(n) time and O(1) space by scanning once and storing mismatch indices.

1. Clarify the problem

Confirm that swaps are only within the first string, and we can use at most 2 swaps. Also confirm that the strings are of equal length.

2. Identify mismatched positions

Scan both strings simultaneously and collect indices where characters differ. If there are 0 mismatches, return true immediately.

3. Analyze mismatch count

If there are exactly 2 mismatches, check if swapping the characters at those indices makes the strings equal. If yes, return true; else false.

4. Handle more than 2 mismatches

If there are 3 or more mismatches, check if a single swap can fix two mismatches (i.e., there exist two indices i and j such that swapping s1[i] and s1[j] reduces the mismatch count by 2). If such a swap exists, apply it and then check if the remaining mismatches can be fixed with one more swap (i.e., exactly 2 mismatches remain that can be fixed by swapping).

5. Return result and discuss complexity

Return true if the mismatches can be resolved with at most 2 swaps, else false. Mention that the solution runs in O(n) time and O(1) space (or O(k) where k is number of mismatches, but k can be up to n).

Key Points to Mention

  • Edge cases: strings already equal (0 swaps), exactly 2 mismatches, and more than 2 mismatches where a swap fixes two at once.
  • Time and space complexity: O(n) time, O(1) space if we only store mismatch indices (at most 4 needed for early exit).
  • The importance of checking if a swap reduces mismatches by 2, and then verifying the remaining mismatches can be fixed with one more swap.
  • Handling cases where mismatches > 4: impossible with 2 swaps, so return false early.
  • Clarifying that swaps are only within the first string, not between strings.
  • Testing with examples: e.g., s1='ab', s2='ba' (1 swap), s1='abcd', s2='badc' (2 swaps), s1='abc', s2='def' (impossible).

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.