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Start by defining a Node class with value and next pointer, then a LinkedList class with head and methods to append and print. For deletion of the max node, traverse the list to find the maximum value and its predecessor, then unlink the node. Finally, write a test that creates a list, deletes the max, and prints the result.
Pro tip: Clarify edge cases upfront—empty list, single node, multiple max values—and state your assumptions (e.g., delete first occurrence). This shows thoroughness and prevents misunderstandings.
Create a Node class with value and next attributes. Create a LinkedList class with a head pointer and methods to append nodes and print the list.
Traverse the list to find the maximum value and keep track of the node before it. Handle edge cases: empty list, max at head, and multiple occurrences (delete first or all? clarify).
If the max node is the head, update head to head.next. Otherwise, set the predecessor's next to the max node's next. Optionally free memory in languages like C/C++.
Create a linked list with sample values (e.g., 3->7->2->9->5). Call deleteMax, then print the list to verify the max (9) is removed.
Mention time complexity O(n) and space O(1). Test edge cases: empty list, single node, max at head, max at tail, duplicate max values.
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