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Apple·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Apr 2026

Summary

Apple SWE interview with a string manipulation problem. Pretty focused session, just the one coding question from what I can tell.

Questions Asked (1)

Q1

Given two strings of equal length, determine whether there is a one-to-one character mapping between them (i.e., are the strings isomorphic).

Algorithms & Data Structures
Author's notes

Classic problem but I still fumbled the edge cases a bit.

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AI HintsAI Generated

Suggested Approach

Clarify the definition of isomorphism: a bijective mapping between characters of both strings. Then propose an efficient solution using two hash maps (or a map and a set) to track mappings in both directions, ensuring consistency. Walk through an example and analyze time/space complexity.

Pro tip: Mention that a single map is insufficient because it only enforces one direction; you need to check both directions to prevent two characters mapping to the same character. Also, discuss edge cases like empty strings and Unicode characters.

1. Clarify the problem

Confirm that isomorphic means a one-to-one correspondence between characters, and that the mapping must be consistent in both directions. Ask about input constraints (e.g., ASCII vs Unicode, length limits).

2. Outline the approach

Propose using two hash maps: one to map characters from the first string to the second, and another for the reverse mapping. Alternatively, use one map and a set to track mapped characters.

3. Walk through an example

Demonstrate with a simple example like 'egg' and 'add' to show how the mappings are built and checked. Highlight the failure case when a conflict arises.

4. Analyze complexity

State that the algorithm runs in O(n) time and O(k) space, where n is the string length and k is the number of distinct characters (bounded by alphabet size).

5. Discuss edge cases and optimizations

Mention handling empty strings, strings of different lengths (though problem states equal length), and potential optimizations like early termination on mismatch.

Key Points to Mention

  • Definition of isomorphic strings: bijective mapping between characters.
  • Use of two hash maps (or one map and a set) to enforce one-to-one mapping.
  • Time complexity O(n) and space complexity O(k) where k is distinct characters.
  • Edge cases: empty strings, strings with repeated characters, Unicode characters.
  • Alternative approach: encode strings by order of first occurrence and compare.
  • Early termination when a conflict is detected.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.