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Weride·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

WeRide software engineer interview focused entirely on math-heavy algorithm problems: matrix multiplication, fast exponentiation, and Fibonacci via matrix exponentiation. Pretty niche stuff, felt more like a competitive programming screen than a typical SWE interview.

Questions Asked (3)

Q1

Implement matrix multiplication for an n×m matrix A and an m×p matrix B, returning the resulting n×p matrix C. Handle modular arithmetic if a MOD value is provided.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Pretty straightforward once you get the dimensions right, but I fumbled the index order on my first pass and had to back up.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem constraints, including matrix dimensions, data types, and whether modular arithmetic is required. Then describe the standard triple-loop algorithm, emphasizing cache-friendly iteration order and the optional modulo operation. Finally, discuss time and space complexity and potential optimizations like blocking or Strassen's algorithm.

Pro tip: Mention that you would use a cache-friendly loop order (i, k, j) to improve performance, and that applying modulo at each addition prevents overflow. This shows awareness of practical implementation details beyond the naive algorithm.

1. Clarify requirements and constraints

Ask about matrix dimensions, data types (e.g., integers, floats), whether MOD is always provided, and any memory or time constraints. Confirm the expected output format.

2. Outline the standard algorithm

Describe the triple-loop approach: for each i in 0..n-1, for each j in 0..p-1, compute sum over k of A[i][k]*B[k][j]. Mention that the order of loops can affect cache performance.

3. Incorporate modular arithmetic

If MOD is provided, apply modulo after each addition (or after each multiplication and addition) to keep numbers small and avoid overflow. Explain that modulo can be applied at the end of each inner loop iteration.

4. Analyze complexity and trade-offs

State that time complexity is O(n*m*p) and space complexity is O(n*p) for the output. Discuss trade-offs: naive vs. optimized (e.g., blocking, Strassen) and when modular arithmetic affects performance.

5. Discuss optimizations and edge cases

Mention cache-friendly loop ordering (i, k, j), blocking for large matrices, and handling edge cases like zero dimensions or empty matrices. Also note that if MOD is not provided, use appropriate data types to avoid overflow.

Key Points to Mention

  • Time complexity O(n*m*p) and space complexity O(n*p).
  • Cache-friendly loop order (i, k, j) to improve performance.
  • Modular arithmetic: apply modulo after each addition to prevent overflow.
  • Edge cases: zero dimensions, empty matrices, and non-integer types.
  • Trade-offs: naive vs. optimized algorithms (e.g., blocking, Strassen).
  • Overflow handling: use 64-bit integers or modular arithmetic when needed.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Implement fast exponentiation: given x, k, and an optional MOD, compute x^k (mod MOD) in O(log k) time. Handle edge cases like k=0 and x=0.

Algorithms & Data Structures
Author's notes

Classic problem but I still had to think for a second about the k=0 edge case when x is also 0.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem constraints and edge cases, then explain the binary exponentiation algorithm using iterative squaring and multiplication. Walk through a small example to demonstrate the O(log k) time complexity and discuss how to handle the optional modulo.

Pro tip: Mention that you can use exponentiation by squaring with bitwise operations for efficiency, and always consider negative exponents if the problem allows them (though not specified here). Also, emphasize the importance of using 64-bit integers to avoid overflow during multiplication when a modulo is applied.

1. Clarify requirements and edge cases

Ask about constraints: can k be negative? Is MOD always positive? What should be returned when MOD is not provided? Confirm handling of k=0 and x=0.

2. Explain the algorithm

Describe binary exponentiation: initialize result to 1, repeatedly square the base and multiply into result when the current bit of k is 1. This reduces time to O(log k).

3. Handle modulo and overflow

If MOD is given, take modulo at each multiplication step to keep numbers small. Use 64-bit integers for intermediate products to prevent overflow.

4. Walk through an example

Pick a small example like x=2, k=10, MOD=1000 and show the steps: k in binary 1010, compute powers, and combine.

5. Discuss complexity and edge cases

State time complexity O(log k) and space O(1). Mention that k=0 returns 1 (if x≠0), and x=0 with k>0 returns 0; if MOD is 1, result is 0.

Key Points to Mention

  • Binary exponentiation (exponentiation by squaring) reduces multiplications from O(k) to O(log k).
  • Iterative implementation using bitwise operations (e.g., while k: if k&1: result = result * base % MOD; base = base * base % MOD; k >>= 1).
  • Modulo arithmetic: apply modulo after each multiplication to prevent overflow and keep numbers manageable.
  • Edge cases: k=0 returns 1 (except when x=0 and k=0, which is ambiguous but typically 1), x=0 with k>0 returns 0, MOD=1 returns 0.
  • Overflow prevention: use 64-bit integers (long long in C++/Java) for intermediate products when MOD is large.
  • Time complexity O(log k) and space complexity O(1).

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

Compute the nth Fibonacci number (n >= 0) using matrix exponentiation to achieve O(log n) time complexity. Apply modular arithmetic where required.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This is where the first two problems clicked together, which was a nice payoff.

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AI HintsAI Generated

Suggested Approach

Start by explaining the matrix exponentiation method for Fibonacci numbers, emphasizing the O(log n) time complexity achieved through fast exponentiation. Then, discuss how to apply modular arithmetic to prevent overflow and meet problem constraints. Finally, walk through the implementation details and analyze trade-offs.

Pro tip: Mention that while matrix exponentiation is optimal for very large n, for small n or when simplicity is key, iterative or fast doubling methods might be preferable. This shows awareness of practical trade-offs.

1. Understand the problem and constraints

Clarify that n can be large, so O(n) is inefficient. Confirm that modular arithmetic is required to handle large numbers.

2. Explain the matrix exponentiation method

Describe how Fibonacci numbers can be computed using the matrix [[1,1],[1,0]] raised to the nth power. Show that the top-left element gives F(n+1).

3. Apply fast exponentiation

Detail the binary exponentiation algorithm to compute the matrix power in O(log n) time, using divide-and-conquer.

4. Incorporate modular arithmetic

Explain that all matrix multiplications should be done modulo a given number (e.g., 10^9+7) to prevent overflow and meet problem requirements.

5. Analyze complexity and trade-offs

State that time complexity is O(log n) and space is O(log n) due to recursion, or O(1) if iterative. Compare with other methods like fast doubling.

Key Points to Mention

  • Matrix exponentiation reduces Fibonacci computation to O(log n) time.
  • The transformation matrix is [[1,1],[1,0]] and its nth power yields F(n+1) and F(n).
  • Binary exponentiation (exponentiation by squaring) is used to compute the matrix power efficiently.
  • Modular arithmetic must be applied at each multiplication step to avoid integer overflow.
  • Edge cases: n=0 returns 0, n=1 returns 1; handle these explicitly.
  • Alternative O(log n) method: fast doubling, which may have lower constant factors.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.