← Robinhood Interview Insights
I went with DFS first which is the obvious move, just count how many times you visit each node.
First, clarify the problem: in a DAG, a node is triggered if there is a path from the root to it. The number of times a node is triggered equals the number of distinct paths from the root to that node. Use dynamic programming (topological order) to compute path counts efficiently, then optimize by only computing for target nodes or using memoization.
Pro tip: Mention that the number of paths can be exponential, so use modulo or big integers as needed. Also, discuss trade-offs between precomputing all nodes vs. computing on-demand for targets.
Confirm that 'triggered' means reachable from root, and the count is the number of distinct paths from root to the node. Ask about constraints: graph size, target set size, and whether counts can be large.
For each target, perform DFS/BFS from root to count paths. This is exponential in worst case and inefficient for large graphs.
Compute path counts for all nodes in topological order: initialize root count to 1, then for each node, add its count to all outgoing neighbors. This is O(V+E) time and space.
If only a few targets, consider reverse graph and memoized DFS from targets to root, or prune nodes not on paths to targets. Discuss trade-offs between precomputation and on-demand.
Use modulo if counts can be huge, or big integers. Handle unreachable targets (count 0), root in target set (count 1), and multiple edges between same nodes (count each edge as separate path).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.