← Databricks Interview Insights
My first instinct was modified Dijkstra and that was right, but I fumbled the tiebreaker logic for a bit.
Model the problem as a shortest path on a state graph where each state is (cell, mode), and edges represent moving to adjacent cells using the same mode or switching modes at the current cell. Use Dijkstra's algorithm with a priority queue ordered by (time, cost) to find the optimal path, ensuring that when times are equal, the lower cost is preferred. Finally, reconstruct the path and return the sequence of cells and modes.
Pro tip: Clarify upfront whether mode switching is allowed only at certain cells (e.g., transfer stations) or anywhere; this assumption drastically changes the graph and algorithm. Also, discuss how to handle large grids by using early termination and bidirectional search if applicable.
Ask about grid size, number of modes, whether switching modes is allowed anywhere or only at specific cells, and if costs/times are static. Confirm the tie-breaking rule: minimize time first, then cost.
Create a state for each (cell, mode) pair. Add edges for moving to adjacent cells with the same mode (using that mode's time and cost) and for switching modes at the same cell (with zero time and cost, unless specified otherwise).
Use Dijkstra's algorithm because edge weights (time) are non-negative. Maintain a priority queue keyed by (time, cost) to handle the tie-breaking. Mention that A* with a heuristic could be used if performance is critical.
When relaxing edges, if a new path has equal time but lower cost, update the state. Keep parent pointers to reconstruct the optimal path, including mode switches.
State that the time complexity is O((V+E) log V) where V = cells × modes and E is the number of transitions. Discuss potential optimizations like early termination when the destination is reached, bidirectional search, or using a heuristic.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.