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Classic question but the Unicode piece is where I fumbled.
Start by clarifying the problem (e.g., substring vs. subsequence, character set) and then present the sliding window technique with a hash map to track the last seen index of each character. Walk through the algorithm step-by-step, emphasizing how the window expands and contracts to maintain uniqueness, and then analyze time and space complexity. Finally, discuss Unicode handling by considering code points and using appropriate data structures.
Pro tip: Mention that the hash map stores the last index of each character to avoid shrinking the window one step at a time, making the solution truly O(n). Also, proactively bring up Unicode normalization and grapheme clusters to show depth beyond the typical ASCII assumption.
Ask whether the string can be empty, what character set to assume (ASCII vs. Unicode), and confirm that we need the length of the longest substring without repeating characters. Discuss edge cases like empty string, all unique characters, and all same characters.
Describe maintaining a window [left, right) that contains no duplicate characters. Use a hash map to store the last seen index of each character. When a duplicate is found, move left to max(left, last_seen[char] + 1) to skip past the previous occurrence.
Trace the algorithm on a sample string like 'abcabcbb' to demonstrate how the window and max length update. Show how the hash map is updated and how left jumps efficiently.
State that each character is visited at most twice (once by right, once by left), so time is O(n). Space is O(min(n, m)) where m is the size of the character set (e.g., 128 for ASCII, 1,114,112 for Unicode code points).
Explain that Unicode characters can be represented as code points (e.g., in Python, strings are sequences of code points). Use a hash map keyed by code point. Mention that grapheme clusters (e.g., emoji with modifiers) may require more advanced handling, but for this problem, code points are typically sufficient.
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