I jumped to a trie pretty fast which felt right, but then the update case tripped me up.
Start by clarifying requirements (e.g., expected scale, update frequency, prefix query frequency) and then propose a trie-based solution where each node stores the sum of values in its subtree. Explain how put, get, and sumByPrefix work in O(L) time (L = key length), and discuss handling updates by adjusting sums along the path.
Pro tip: Mention that you can optimize memory by storing values only at leaf nodes and sums at internal nodes, and consider using a hash map for O(1) get if memory allows. Also, discuss concurrency and persistence if relevant to Snapchat's scale.
Ask about expected data size, read/write ratio, latency requirements, and whether keys are strings. This shows you think before coding.
Propose a trie (prefix tree) where each node stores the sum of all values in its subtree. Alternatively, mention a hash map + sorted list for prefix sums, but highlight trie's efficiency for prefix queries.
Explain put: traverse/create nodes, update value and adjust sums along the path. get: traverse to node and return value. sumByPrefix: traverse to prefix node and return its stored sum.
When updating an existing key, compute the difference between new and old value, then update the sum at each node along the path by adding the difference.
State time complexity O(L) for all operations, space O(total characters). Discuss trade-offs: trie uses more memory but gives fast prefix sums; hash map is faster for get but slower for prefix queries.
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