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Disney·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jul 2026

Summary

Disney SWE interview that was pretty much a BFS problem dressed up with a lot of follow-up questions. More depth required than I expected for what looked like a straightforward grid traversal problem.

Questions Asked (4)

Q1

Implement a function to find the shortest path length in an unweighted 2D grid from the top-left to the bottom-right cell, where '0' is open and '1' is a wall, movement is four-directional, and the function returns -1 if no path exists.

Algorithms & Data Structures
Author's notes

I jumped straight to BFS which was correct, but I fumbled explaining *why* BFS and not DFS for a second.

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AI HintsAI Generated

Suggested Approach

Use BFS from the start cell, exploring all four directions level by level, since BFS guarantees the shortest path in an unweighted grid. Track visited cells to avoid cycles, and return the distance when reaching the bottom-right cell, or -1 if the queue is exhausted.

Pro tip: Clarify edge cases upfront (e.g., start or end is a wall, single-cell grid) and mention that BFS is optimal for unweighted grids while DFS would not guarantee shortest path. Also, discuss space-time trade-offs and potential optimizations like bidirectional BFS if the grid is large.

1. Clarify problem and edge cases

Confirm grid dimensions, movement rules, and what constitutes a valid path. Discuss edge cases: start or end is a wall, grid is 1x1, or no path exists.

2. Choose BFS and explain why

State that BFS is ideal for unweighted shortest path because it explores nodes in increasing order of distance from the start. Mention that DFS or Dijkstra would be less efficient or unnecessary.

3. Outline BFS algorithm

Initialize a queue with the start cell and a visited set or matrix. While the queue is not empty, dequeue a cell, check if it's the target, and enqueue all valid unvisited neighbors with distance+1.

4. Handle boundaries and walls

For each neighbor, check if it's within grid bounds, not a wall ('1'), and not visited. Mark visited upon enqueue to avoid duplicates.

5. Return result and discuss complexity

If target is reached, return its distance; otherwise return -1. Analyze time and space complexity: O(R*C) for both, where R and C are grid dimensions.

Key Points to Mention

  • BFS guarantees shortest path in unweighted graphs
  • Use a queue for level-order traversal
  • Track visited cells to avoid infinite loops
  • Check boundaries and wall conditions before enqueueing
  • Time and space complexity: O(R*C)
  • Edge cases: start/end is wall, no path, single cell

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Why is BFS the right algorithm here, and what are the time and space complexities?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Recovered fine on this after the earlier stumble.

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AI HintsAI Generated

Suggested Approach

First, clarify the problem context and why BFS is suitable (e.g., shortest path in unweighted graph, level-order traversal). Then, derive the time and space complexities based on the graph representation and BFS mechanics, explaining each component.

Pro tip: Mention that BFS is optimal for unweighted graphs but not for weighted graphs (where Dijkstra's is needed), and note that the space complexity can be reduced if the graph is a tree or if we only need to check existence.

1. Clarify the problem

Restate the problem to ensure understanding, and identify the key characteristics (e.g., unweighted graph, need shortest path, level-order processing).

2. Justify BFS choice

Explain why BFS is appropriate: it explores nodes in order of distance from the source, guaranteeing shortest path in unweighted graphs, and naturally handles level-order traversal.

3. Analyze time complexity

Break down time complexity: O(V + E) for adjacency list, O(V^2) for adjacency matrix. Explain that each vertex and edge is processed once.

4. Analyze space complexity

Discuss space complexity: O(V) for the queue and visited set, plus O(V + E) for the graph representation if not already given.

5. Summarize and compare

Summarize why BFS is the right choice, and briefly compare with alternatives like DFS or Dijkstra's to highlight trade-offs.

Key Points to Mention

  • BFS guarantees shortest path in unweighted graphs
  • Time complexity: O(V + E) with adjacency list, O(V^2) with adjacency matrix
  • Space complexity: O(V) for queue and visited set, plus graph storage
  • BFS explores level by level, suitable for finding shortest path or minimum steps
  • Comparison with DFS: BFS uses more memory but finds shortest path
  • Edge cases: disconnected graphs, cycles, and large graphs

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

What edge cases would you consider for this problem, including single-cell grids, blocked start or end, and multiple valid shortest paths?

Algorithms & Data Structures
Author's notes

The multiple shortest paths one was a bit of a curveball.

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AI HintsAI Generated

Suggested Approach

Start by restating the problem and its constraints, then systematically enumerate edge cases across input dimensions (size, boundaries, obstacles, start/end conditions) and algorithmic concerns (multiple paths, tie-breaking, unreachable targets). For each edge case, briefly explain how your solution handles it and why it matters for correctness or efficiency.

Pro tip: Tie each edge case back to a concrete test you would write, showing you think like a test engineer as well as an algorithm designer. Mention that at Disney, where correctness and reliability are paramount, proactively handling edge cases prevents costly bugs in production.

1. Clarify the problem and constraints

Restate the problem (e.g., shortest path in a grid) and confirm assumptions about grid size, movement rules, and obstacle representation. This sets the stage for identifying relevant edge cases.

2. Enumerate input-related edge cases

List cases like 1x1 grid, empty grid, start or end blocked, start equals end, no path, and multiple valid shortest paths. Explain how each affects your algorithm.

3. Consider algorithmic and performance edge cases

Discuss cases that impact complexity: large grids, many obstacles, diagonal movement, negative weights (if applicable), and tie-breaking when multiple shortest paths exist.

4. Explain handling and validation

For each edge case, describe how your solution detects and handles it (e.g., early return, special checks) and what the expected output should be.

5. Summarize and connect to testing

Wrap up by emphasizing that these edge cases inform your test suite, ensuring robustness and correctness in production.

Key Points to Mention

  • Single-cell grid: start equals end, return 0 or empty path.
  • Blocked start or end: immediately return no path or throw exception.
  • Multiple valid shortest paths: algorithm should return any one, but be aware of tie-breaking rules.
  • Unreachable target: return -1 or appropriate sentinel value.
  • Grid boundaries and movement constraints: ensure no out-of-bounds access.
  • Performance implications: large grids, dense obstacles, and use of BFS vs. Dijkstra.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q4

How would you extend this solution to support diagonal movement, and what specifically needs to change in the implementation?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Just swap the directions array from 4 neighbors to 8.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the original solution's context (e.g., grid-based pathfinding, game movement, or matrix traversal) and then systematically identify the components that assume orthogonal movement. Explain how to generalize those components to include diagonal moves, focusing on neighbor generation, cost models, and validity checks, while discussing trade-offs like performance and correctness.

Pro tip: Mention that diagonal movement often requires adjusting cost calculations (e.g., using √2 for Euclidean distance) and handling corner-cutting constraints, which shows you understand real-world implications beyond just adding new directions.

1. Clarify the original solution

Briefly restate the problem and the current approach, highlighting assumptions about movement (e.g., only up/down/left/right). This ensures you and the interviewer are aligned on the baseline.

2. Identify components to modify

List the specific parts that need changes: neighbor generation, movement cost, validity checks (e.g., obstacles, boundaries), and any data structures or algorithms (like BFS, Dijkstra, A*).

3. Propose implementation changes

Describe how to extend each component: add diagonal offsets to neighbor lists, update cost functions (e.g., √2 for diagonals), and adjust validity checks to prevent corner-cutting if needed.

4. Discuss trade-offs and edge cases

Address performance implications (e.g., more neighbors increase branching factor), correctness (e.g., ensuring no illegal moves), and potential optimizations (e.g., precomputed directions).

5. Summarize and verify

Conclude with a concise summary of changes and suggest testing strategies (e.g., unit tests for diagonal moves, performance benchmarks) to validate the extension.

Key Points to Mention

  • Neighbor generation: add four diagonal directions (e.g., (-1,-1), (-1,1), (1,-1), (1,1)) to the existing orthogonal ones.
  • Cost model: if using weighted graphs, diagonal moves should have cost √2 (or 1.4) instead of 1 to reflect Euclidean distance; for unweighted, cost remains 1 but may affect optimality.
  • Validity checks: ensure diagonal moves don't pass through obstacles (corner-cutting) unless allowed; check both adjacent cells for obstacles.
  • Algorithm adjustments: for BFS, diagonal moves may require a different queue handling or distance metric; for A*, update heuristic (e.g., use Chebyshev or octile distance).
  • Performance impact: branching factor increases from 4 to 8, potentially increasing time and space complexity; consider optimizations like pruning or bidirectional search.
  • Testing: add test cases for diagonal paths, blocked diagonals, and performance comparisons to ensure correctness and efficiency.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.