← Plymouth Rock Assurance Corporation Interview Insights
The key is recognizing this is a reverse cumulative sum partitioned by policy.
Clarify the table schema and the definition of 'subsequent terms' (e.g., by term number or date). Then use a window function like SUM() OVER (PARTITION BY policy_id ORDER BY term_id ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING) to compute the cumulative sum from the current term to the last term for each policy.
Pro tip: Mention that in insurance, 'ultimate loss' often includes IBNR and development factors, but for this SQL exercise, focus on the cumulative sum and confirm the ordering column. Also, consider performance implications for large datasets and suggest indexing on (policy_id, term_id).
Identify the table columns: policy_id, term_id (or term date), and loss_amount. Confirm that 'subsequent terms' means terms with a higher term_id or later date within the same policy.
Use a window function to compute a running total from the current row to the end of the partition. Alternatively, a self-join or correlated subquery can work but may be less efficient.
Construct: SELECT policy_id, term_id, loss_amount, SUM(loss_amount) OVER (PARTITION BY policy_id ORDER BY term_id ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING) AS ultimate_loss FROM table;
Check for ties in term_id (use additional ordering if needed), null loss amounts (treat as 0), and ensure the result is correct for the last term (should equal its own loss).
Discuss indexing on (policy_id, term_id) for performance. Explain the window frame and why it computes the desired cumulative sum.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.