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Google·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Interviewed for a data engineering role at Google and got the classic climbing stairs problem. Pretty standard coding screen, nothing that surprised me.

Questions Asked (1)

Q1

Given a staircase with n steps, how many distinct ways can you climb to the top if you can take either 1 or 2 steps at a time?

Algorithms & Data Structures
Author's notes

Classic dynamic programming setup.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem and defining the recurrence relation: the number of ways to reach step n is the sum of ways to reach step n-1 and step n-2. Then, discuss multiple solutions from naive recursion to dynamic programming with O(n) time and O(1) space, highlighting the Fibonacci sequence connection.

Pro tip: Mention that this is essentially the Fibonacci sequence, and you can optimize space to O(1) by only keeping the last two values. Also, discuss how to handle large n with modular arithmetic if needed.

1. Clarify the problem

Confirm that n is a positive integer, and that the order of steps matters (e.g., 1+2 and 2+1 are distinct). Also, check if n=0 is considered (usually 1 way).

2. Derive recurrence relation

Let f(n) be the number of ways to reach step n. Then f(n) = f(n-1) + f(n-2), with base cases f(1)=1, f(2)=2.

3. Discuss naive recursive solution

Explain that a simple recursive solution has exponential time complexity due to overlapping subproblems, which is inefficient for large n.

4. Present dynamic programming solutions

Show how to use memoization (top-down) or tabulation (bottom-up) to achieve O(n) time and O(n) space. Then optimize to O(1) space by keeping only the last two values.

5. Analyze complexity and edge cases

State time and space complexity, and discuss edge cases like n=0, n=1, and potential integer overflow for large n (suggest modular arithmetic).

Key Points to Mention

  • Recurrence relation: f(n) = f(n-1) + f(n-2)
  • Base cases: f(1)=1, f(2)=2 (and f(0)=1 if considered)
  • Connection to Fibonacci sequence (shifted by one index)
  • Time and space complexity: O(n) time, O(1) space with iterative approach
  • Handling large n with modulo (e.g., 10^9+7) to prevent overflow
  • Alternative solutions like matrix exponentiation for O(log n) time

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.