I knew binary search was involved pretty quickly, the tricky part was nailing down the bounds.
Recognize that the minimum capacity lies between the maximum package weight and the sum of all weights. Use binary search on this range, and for each candidate capacity, simulate the shipping process to check if all packages can be shipped within D days. The first feasible capacity found is the minimum.
Pro tip: Clarify that packages must be shipped in the given order, and emphasize that the binary search reduces time complexity to O(n log(sum - max)). Mention that this is optimal because the feasibility check is monotonic: if a capacity works, any larger capacity also works.
Set low to the maximum package weight (since a ship must carry at least the heaviest package) and high to the sum of all weights (one day shipping).
While low < high, compute mid = low + (high - low) / 2 and check if mid is feasible.
Simulate loading packages in order: accumulate weights until adding the next would exceed capacity, then increment day count and start a new day. If days needed <= D, capacity is feasible.
If feasible, set high = mid; else set low = mid + 1. Continue until low == high.
The minimum capacity is low (or high, since they are equal).
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