This wrecked me a little because I started thinking BFS and they clearly wanted something more principled.
Model the problem as a system of linear equations over GF(2), where each variable represents whether a cell is toggled. Solve for the toggle vector that transforms the start to the target, then minimize the number of 1s in that vector. If the system is inconsistent, it's impossible.
Pro tip: Mention that the toggle matrix is symmetric and often has a unique solution for many grid sizes, but for certain dimensions (e.g., 5x5) there are multiple solutions; use Gaussian elimination to find the solution space and then minimize the Hamming weight.
Define variables x_{i,j} ∈ {0,1} indicating whether to toggle cell (i,j). For each cell, the net toggle it receives is the sum (mod 2) of its own x and the x's of its orthogonal neighbors. This must equal the difference between start and target at that cell.
Write the system as A x = b over GF(2), where A is the (mn)×(mn) toggle matrix and b is the vector of required flips. Use Gaussian elimination to determine if a solution exists and to find the solution space.
If solutions exist, the solution space is an affine subspace. Enumerate all solutions (or use linear programming over GF(2) with branch and bound) to find the one with the fewest 1s, i.e., minimum toggles.
If the system is inconsistent, return impossible. Discuss time complexity: Gaussian elimination is O((mn)^3) which is fine for small grids; for large grids, exploit structure (e.g., first row determines rest) to reduce to O(2^n * m).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.