The naive recursive solution is the obvious wrong answer and I knew that, so I jumped to the iterative approach pretty fast.
Start by clarifying the problem constraints (n up to 10^6, 0-indexed) and then present an iterative O(n) time, O(1) space solution using two variables. Explain the complexity and discuss handling large numbers with arbitrary-precision arithmetic or modular arithmetic if needed.
Pro tip: Mention that for n=10^6, the Fibonacci number has about 208,988 digits, so native types overflow; use Python's built-in big integers or a library like GMP. Also, note that if only the last k digits are needed, you can use modular arithmetic to keep numbers small.
Confirm that n is 0-indexed, n can be up to 10^6, and discuss whether the result needs to be exact or modulo something. Ask about the expected return type and any memory constraints.
Select an iterative approach with O(n) time and O(1) space, as it is simple and efficient for n up to 10^6. Mention alternatives like matrix exponentiation (O(log n)) but note that for n=10^6, O(n) is perfectly fine and avoids overhead.
Write a function that initializes two variables (a=0, b=1) and iterates n times, updating a and b. Handle edge cases (n=0, n=1) and ensure the code is clean and efficient.
Explain that the iterative solution runs in O(n) time and O(1) space, as it only uses a constant number of variables. Note that the time is linear in n, which is acceptable for n=10^6.
Discuss that Fibonacci numbers grow exponentially, so for n=10^6, the result has ~208,988 digits. Native integer types overflow; use arbitrary-precision arithmetic (e.g., Python's int, Java's BigInteger, or GMP). If only modulo is needed, use modular arithmetic to keep numbers small.
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