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Google·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Apr 2026

Summary

Google SWE interview, coding round focused on graph traversal. One question, no implementation needed, just walk through the approach and complexity. Pretty straightforward if you've done any BFS prep.

Questions Asked (1)

Q1

You have an N×N grid where 1 is water and 0 is land. Given a start cell and a target cell, find the shortest path between them moving only through land cells in 4 directions. Describe your approach and analyze time and space complexity. No code required.

Algorithms & Data Structures
Author's notes

Classic BFS setup.

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AI HintsAI Generated

Suggested Approach

Model the grid as an unweighted graph and use BFS from the start cell to find the shortest path to the target, exploring only land cells in 4 directions. Track visited cells to avoid cycles and stop early when the target is reached. Then analyze time and space complexity based on the number of cells.

Pro tip: Mention that BFS is optimal for unweighted graphs and briefly compare with DFS or A* to show depth of understanding. Also, clarify edge cases like start or target being water, or unreachable target.

1. Clarify the problem and constraints

Confirm that movement is only through land cells (0) in 4 directions, and that start and target are valid land cells. Discuss edge cases like start equals target, start or target is water, or no path exists.

2. Choose BFS as the algorithm

Explain that BFS is ideal for finding the shortest path in an unweighted graph, as it explores level by level. Mention that each cell is a node and edges connect adjacent land cells.

3. Describe the BFS process

Initialize a queue with the start cell and a visited set. While the queue is not empty, dequeue a cell, check if it's the target, and enqueue all unvisited adjacent land cells. Track distance or parent pointers to reconstruct the path if needed.

4. Analyze time and space complexity

Time complexity is O(N^2) since each cell is visited at most once. Space complexity is O(N^2) for the visited set and queue in the worst case.

5. Discuss optimizations and alternatives

Mention bidirectional BFS for faster performance, or A* with Manhattan distance heuristic if the grid is large. Note that DFS would not guarantee shortest path.

Key Points to Mention

  • BFS guarantees shortest path in unweighted graphs
  • Use a queue for BFS and a visited set to avoid revisiting cells
  • Time complexity: O(N^2) because each cell is processed once
  • Space complexity: O(N^2) for queue and visited set in worst case
  • Edge cases: start/target water, unreachable target, start equals target
  • Possible optimizations: bidirectional BFS or A* with Manhattan distance

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.