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I stared at this for a second because my instinct was to split evenly, like 50 red and 50 blue in each basket, and then I realized that gives you 50/100 times 50/100 which is just 25%.
Define the probability as the product of the probabilities of drawing a red ball from each basket, then optimize the distribution by considering extreme cases. Recognize that putting a single red ball in one basket and all remaining balls in the other maximizes the product, and compute the resulting probability.
Pro tip: After presenting the solution, mention that this is a classic optimization problem that tests your ability to think probabilistically and consider edge cases, which is directly applicable to A/B testing and risk modeling in data science.
Let basket 1 contain r1 red and b1 blue balls, basket 2 contain r2 red and b2 blue balls, with r1+r2=100 and b1+b2=100. The probability of drawing red from both baskets is (r1/(r1+b1)) * (r2/(r2+b2)).
To maximize the product, consider putting all balls of one color in one basket and the other color in the other, or isolating a single red ball. Test the case where one basket has 1 red and 0 blue, and the other has 99 red and 100 blue.
For basket 1: 1 red, 0 blue → probability of red = 1. For basket 2: 99 red, 100 blue → probability of red = 99/199. The product is 1 * (99/199) = 99/199 ≈ 0.4975.
Argue that any other distribution yields a lower probability. For instance, if both baskets have a mix, the product is less than 0.5, and the extreme case achieves nearly 0.5. Use calculus or logical reasoning to confirm that the maximum occurs at the boundary.
The maximum probability is 99/199, approximately 0.4975 or 49.75%.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.