Classic two-sum, you'd think it's autopilot but the edge cases tripped me up a bit.
Use a hash map to store each element's value and index as you iterate through the array. For each element, check if the complement (target - current element) exists in the map; if so, return the two indices. This achieves O(n) time and O(n) space.
Pro tip: Clarify upfront whether the array is sorted or if there are constraints like duplicate values or multiple valid pairs. Mentioning edge cases like empty array or no solution shows thoroughness and can guide your implementation.
Ask about input size, whether the array is sorted, if there are duplicate values, and if multiple valid pairs exist. Confirm the expected return type and edge cases.
Select a hash map (dictionary) to store values and indices for O(1) lookups, enabling a single-pass solution.
Traverse the array once; for each element, compute the complement and check if it's already in the hash map. If found, return the stored index and current index.
If no pair is found after the loop, return an empty array. Ensure indices are distinct and consider duplicate values correctly.
State time and space complexity (O(n) each). Walk through a small example and test edge cases like empty array, no solution, and negative numbers.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.