I went straight to the sweep-line idea, which felt right, +passengers at start and -passengers at end, sort all events, scan through.
Model each trip as two events: a pickup at the start location and a drop-off at the end location. Sort all events by location, and for events at the same location, process drop-offs before pickups to avoid false capacity violations. Then sweep through the sorted events, maintaining a running passenger count and checking against the capacity.
Pro tip: Explicitly discuss the tie-breaking rule for events at the same coordinate—processing drop-offs before pickups is crucial because a passenger getting off at a location frees capacity for another passenger getting on at the same location. This shows attention to edge cases and real-world correctness.
Restate the problem to ensure understanding: trips are one-directional, capacity is fixed, and we need to check if capacity is ever exceeded. Ask about constraints (e.g., number of trips, coordinate ranges) and confirm the tie-breaking rule for same-coordinate events.
Explain that each trip can be split into two events: a pickup (+passenger count) at the start and a drop-off (-passenger count) at the end. This transforms the problem into a sweep-line over sorted events.
Sort events by location. For events at the same location, process drop-offs before pickups. This ensures that capacity is freed before new passengers board, preventing false positives.
Iterate through sorted events, updating the current passenger count. After each event, check if the count exceeds capacity; if so, return false. If the sweep completes without violation, return true.
State that sorting takes O(n log n) time and O(n) space for events. Discuss edge cases: empty trips, zero capacity, trips with zero passengers, and multiple events at the same coordinate.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.