The case-insensitivity thing is what makes it non-trivial.
Clarify the definition of a 'word' (e.g., split on whitespace) and confirm that output should preserve original casing from the first occurrence. Use a hash map to track each word's lowercase form and its original casing, then compute the symmetric difference between the two sets.
Pro tip: Mention that you'd use a case-insensitive comparison by normalizing to lowercase, but store the original casing to return. Also, discuss handling duplicates: if a word appears multiple times in one string but not the other, it should still be returned once.
Ask about word delimiters (whitespace, punctuation), case sensitivity, and output format (order, duplicates). Confirm that words are case-insensitive for comparison but original casing is preserved.
Use a hash map (dictionary) to map lowercase words to their original casing for each string. Alternatively, use sets for efficient symmetric difference, but keep a separate map for casing.
Split each string into words, iterate through them, and populate the maps. For each word, store the lowercase version as key and the original word as value (first occurrence).
Find words that are in one map but not the other. Collect the original casing from the map where the word exists.
Return the list of words, ensuring no duplicates and preserving the original casing. Discuss order (e.g., order of appearance in first string then second).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.