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I knew the three-pointer approach going in, but I fumbled explaining the loop invariant while coding it.
Use the Dutch National Flag algorithm with three pointers: low, mid, and high. Iterate through the array with mid, swapping elements to maintain three regions: 0s before low, 1s between low and mid, and 2s after high. This sorts the array in a single pass with constant space.
Pro tip: Emphasize that this is a classic partitioning problem and that the algorithm is optimal in time and space. Mention that it's also known as the Dutch National Flag problem, showing familiarity with standard algorithmic patterns.
Restate the problem to ensure understanding: sort an array of 0s, 1s, and 2s in-place, single pass, constant space. Confirm that the array can be modified and that no extra data structures are allowed.
Select the Dutch National Flag algorithm (three-pointer approach) as it meets all constraints. Explain that it partitions the array into three sections: 0s, 1s, and 2s.
Initialize low = 0, mid = 0, high = n-1. Maintain invariants: elements before low are 0, elements between low and mid are 1, elements after high are 2, and the unexplored region is between mid and high.
While mid <= high, inspect arr[mid]. If it's 0, swap with arr[low] and increment both low and mid. If it's 1, just increment mid. If it's 2, swap with arr[high] and decrement high (do not increment mid).
State that time complexity is O(n) and space is O(1). Discuss edge cases like empty array, all same elements, or already sorted array.
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