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Meta·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Three coding problems in one Meta session, ranging from interval coverage to BST range queries to a log-parsing stack problem. Nothing felt impossible but the follow-up on the BST question is where I think I left points on the table.

Questions Asked (3)

Q1

Given an integer range [-M, M] and a list of inclusive integer intervals, find any integer in that range with the maximum coverage count across all intervals.

Algorithms & Data Structures
Author's notes

My first instinct was to just expand every interval and count hits in an array, which works but I knew they'd push back on it if M is huge.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints and edge cases, then propose an efficient sweep-line algorithm using a difference array or event sorting to compute coverage counts in O(N log N) or O(N + M) time. Walk through the algorithm step-by-step, analyze time and space complexity, and discuss potential optimizations or alternative approaches.

Pro tip: Demonstrate awareness of integer overflow and boundary conditions (e.g., intervals extending beyond [-M, M]) and proactively suggest clamping or validation. Also, mention that if multiple integers have the same maximum coverage, returning any is acceptable, showing attention to problem details.

1. Clarify requirements and constraints

Ask about input size, interval inclusivity, whether intervals can overlap or be invalid, and if the range [-M, M] is guaranteed to contain at least one integer. Confirm that any integer with maximum coverage is acceptable.

2. Choose an efficient algorithm

Propose a sweep-line approach: create events for interval starts (+1) and ends+1 (-1), sort them, and sweep to track coverage. Alternatively, use a difference array if M is small, or a segment tree for dynamic updates.

3. Walk through the algorithm

Explain how to process events: sort by coordinate, iterate while maintaining a running sum, and record the coordinate with the highest sum. Handle ties by returning the first or any.

4. Analyze complexity and edge cases

State time complexity O(N log N) for sorting events (or O(N + M) with difference array) and space O(N). Discuss edge cases: empty intervals, intervals outside range, all intervals disjoint, and multiple max points.

5. Discuss optimizations and alternatives

Mention potential optimizations like coordinate compression if M is large, or using a balanced BST for dynamic intervals. Compare with brute-force O(N*M) approach to highlight efficiency.

Key Points to Mention

  • Sweep-line algorithm with event sorting (start +1, end+1 -1)
  • Difference array technique for small M
  • Time complexity O(N log N) vs O(N + M)
  • Handling intervals that extend beyond [-M, M] by clamping
  • Edge cases: empty intervals, all intervals disjoint, multiple max points
  • Integer overflow considerations when summing coverage counts

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given the root of a BST and two integers low and high, return the sum of all node values in that range. Follow-up: if the tree is huge and you need to handle many different range queries, how would you preprocess it?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

The base problem I got through fine, just prune left subtree if node value is below low and right subtree if above high.

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AI HintsAI Generated

Suggested Approach

Start by explaining the optimal recursive traversal that prunes branches outside the range, achieving O(log n + k) time. Then discuss the follow-up by proposing preprocessing techniques like flattening the BST into a sorted array and using prefix sums for O(log n) per query, or augmenting nodes with subtree sums for O(log n) queries without extra space.

Pro tip: Mention that pruning is key: if the current node's value is less than low, skip its left subtree; if greater than high, skip its right subtree. This shows you understand BST properties deeply.

1. Clarify the problem and constraints

Ask about the tree size, number of queries, and whether the tree is static or dynamic. This informs the choice of preprocessing.

2. Explain the optimal single-query approach

Describe a recursive function that traverses only nodes within the range, pruning subtrees that cannot contain valid nodes. Analyze time complexity as O(log n + k) where k is the number of nodes in range.

3. Discuss preprocessing for multiple queries

Propose flattening the BST into a sorted array and building a prefix sum array. Then each range query becomes a binary search for indices and a prefix sum difference, O(log n) per query.

4. Consider space-time trade-offs

Compare the flattening approach (O(n) extra space) with augmenting nodes with subtree sums (O(1) extra space but O(log n) per query). Mention that augmented trees can also handle updates if needed.

5. Summarize and conclude

Reiterate the best approach based on constraints and highlight the importance of pruning and preprocessing for scalability.

Key Points to Mention

  • BST property: left subtree values < node < right subtree values
  • Pruning: skip left if node.val < low, skip right if node.val > high
  • Time complexity: O(log n + k) for single query, where k is number of nodes in range
  • Preprocessing: flatten to sorted array + prefix sums for O(log n) per query
  • Alternative: augment nodes with subtree sums for O(log n) queries without extra space
  • Trade-offs: space vs. query time, static vs. dynamic tree

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

Given logs of function start and end events with timestamps, compute the exclusive execution time for each function, accounting for nested calls.

Algorithms & Data Structures
Author's notes

Stack problem, pretty standard once you see it.

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AI HintsAI Generated

Suggested Approach

Use a stack to track active function calls, recording each function's start time and accumulating child execution time. When a function ends, its exclusive time is the total elapsed time minus the sum of its children's exclusive times. Process events in chronological order, ensuring timestamps are sorted.

Pro tip: Clarify upfront whether timestamps are inclusive or exclusive and whether logs are guaranteed sorted; handling these edge cases demonstrates attention to detail and prevents incorrect assumptions.

1. Parse and Sort Events

Parse the log entries into structured events (function name, start/end, timestamp). If not guaranteed sorted, sort them by timestamp to ensure correct chronological processing.

2. Initialize Data Structures

Use a stack to maintain the current call stack. Also maintain a map from function name to its accumulated exclusive time, and a map to track the start time of each active call.

3. Process Events with Stack

Iterate through events: on a start event, push the function onto the stack and record its start time. On an end event, pop the function, compute its exclusive time as (end_time - start_time) minus the sum of exclusive times of any nested calls that occurred during this call, and add to its total.

4. Handle Nested Calls

When a nested call ends, its exclusive time is subtracted from the parent's elapsed time. This can be done by maintaining a running total of child exclusive times for each active call or by adjusting the parent's start time to account for child execution.

5. Return Results

After processing all events, return the map of function names to their exclusive execution times. Ensure the stack is empty at the end, indicating balanced start/end events.

Key Points to Mention

  • Stack-based approach to handle nested calls and maintain call hierarchy.
  • Exclusive time calculation: total elapsed time minus sum of children's exclusive times.
  • Handling of timestamps: whether they are inclusive/exclusive and if logs are sorted.
  • Edge cases: multiple top-level functions, deeply nested calls, and functions with no children.
  • Time complexity: O(n) where n is number of events, assuming sorting is not needed or O(n log n) if sorting required.
  • Space complexity: O(d) where d is maximum depth of call stack, plus O(f) for function map.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.