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The no-library constraint is the whole point of this question and I almost glossed over it.
Clarify the input format and window definition, then propose a two-pass solution: first compute the day offset for each record by parsing the ISO date string manually, then aggregate amounts into a hash map keyed by shopper ID and day offset. Finally, pivot the aggregated data into rows with columns d0–d6, filling missing days with zero.
Pro tip: Mention that you would validate the date string format and handle edge cases like invalid dates or out-of-window records early, and discuss how the solution scales if the window size changes from 7 days to N days.
Confirm the exact format of the ISO date string, how the 7-day window is defined (e.g., start date provided or derived from data), and whether the output should be sorted or include all shoppers seen.
Manually extract year, month, and day from the ISO string (e.g., 'YYYY-MM-DD') using string slicing and integer conversion, then compute the day offset relative to the window start by converting to a day number (e.g., days since epoch) using arithmetic.
Use a hash map (dictionary) where keys are shopper IDs and values are arrays of length 7 (or another map) to accumulate sums for each day offset; skip records outside the window.
Iterate over the hash map to produce one row per shopper, with columns d0–d6 initialized to zero and populated from the aggregated sums; ensure all shoppers have a row even if they have no transactions in some days.
State that time complexity is O(n) for n records (assuming constant-time hash operations) and space complexity is O(m * 7) for m shoppers; discuss potential optimizations like using a fixed-size array for days if window size is known.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.