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LinkedIn·Machine Learning Engineer·Technical Phone Screen·Senior

SeniorPrefer not to say
Jul 2026

Summary

LinkedIn MLE interview with a probability/geometry question that sounds straightforward but has a real gotcha buried in it. Not a coding marathon, more of a math reasoning session.

Questions Asked (1)

Q1

How would you sample a point (x, y) uniformly at random from the area of a circle with radius R centered at the origin? Why does picking the radius uniformly from [0, R] fail, and what's the correct approach?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

I knew something was off with the naive approach but couldn't articulate it cleanly at first.

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AI HintsAI Generated

Suggested Approach

Start by explaining the intuitive but incorrect method of picking radius uniformly and angle uniformly, then show why it fails due to non-uniform area distribution. Present the correct method using inverse transform sampling: sample radius with density proportional to r, i.e., r = R * sqrt(U), and angle uniformly. Optionally, mention alternative methods like rejection sampling or using two Gaussian variables.

Pro tip: Emphasize that the probability of a point falling in a region is proportional to its area, so the radial density must be linear in r. This demonstrates deep understanding of probability density transformations, a key skill for ML engineers.

1. Explain the naive approach and its flaw

Describe picking radius uniformly from [0, R] and angle uniformly from [0, 2π). Point out that this over-samples the center because the area of an annulus grows with radius, so uniform radius does not yield uniform area density.

2. Derive the correct radial distribution

Show that for uniform area, the probability density of radius r is proportional to r, i.e., f(r) = 2r/R^2 for 0 ≤ r ≤ R. This comes from the area element dA = r dr dθ.

3. Apply inverse transform sampling

Compute the CDF F(r) = r^2/R^2 and invert it: r = R * sqrt(U), where U ~ Uniform(0,1). Combine with θ = 2π V, V ~ Uniform(0,1).

4. Mention alternative methods

Briefly note other valid approaches: rejection sampling (sample in square and reject outside circle) or using two independent standard normal variables and normalizing to radius R.

5. Discuss trade-offs and applications

Compare efficiency: inverse transform is O(1) and exact, rejection sampling may be less efficient but simpler. Relate to ML contexts like sampling from distributions or generating synthetic data.

Key Points to Mention

  • Area element in polar coordinates: dA = r dr dθ, leading to radial density proportional to r.
  • Inverse transform sampling: r = R * sqrt(U) for U ~ Uniform(0,1).
  • Why uniform radius fails: it ignores the increasing circumference at larger radii, causing center bias.
  • Alternative: rejection sampling by sampling uniformly in square [-R,R]^2 and rejecting points outside circle.
  • Alternative: using two independent Gaussians (Box-Muller) and scaling to radius R.
  • Efficiency and exactness: inverse transform is O(1) and exact, while rejection sampling has acceptance probability π/4 ≈ 0.785.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.