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Meta·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
May 2026

Summary

Meta software engineer coding round, one tree problem the whole session. Pretty standard DFS territory but there's enough edge cases to trip you up if you're not careful.

Questions Asked (1)

Q1

Given the root of a binary tree where nodes can hold negative values, return a list of all root-to-leaf path sums.

Algorithms & Data Structures
Author's notes

Spent the first minute overcomplicating it in my head.

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AI HintsAI Generated

Suggested Approach

Use a depth-first search (DFS) traversal to explore all root-to-leaf paths, maintaining a running sum. When a leaf node is reached, add the current sum to the result list. This approach naturally handles negative values and ensures each path is considered exactly once.

Pro tip: Clarify with the interviewer whether the tree can be empty and what should be returned in that case. Also, mention that you can optimize space by using an iterative approach with a stack if recursion depth is a concern.

1. Clarify the problem

Ask about edge cases: empty tree, single node, and whether the tree is balanced. Confirm that a root-to-leaf path must end at a leaf (node with no children).

2. Choose traversal method

Decide between recursive DFS (simpler) or iterative DFS/BFS. Explain that DFS is ideal because it naturally tracks the path sum from root to current node.

3. Implement the algorithm

Write a recursive function that takes a node and the current sum. If the node is a leaf, add the sum to the result. Otherwise, recurse on left and right children with updated sum.

4. Test with examples

Walk through a small tree with negative values to verify correctness. Check edge cases like empty tree and single node.

5. Analyze complexity

State that time complexity is O(N) where N is number of nodes, and space complexity is O(H) for recursion stack, where H is tree height.

Key Points to Mention

  • Depth-first search (DFS) traversal
  • Handling negative values (no special treatment needed)
  • Leaf node condition: node with no left and right children
  • Recursive vs iterative implementation trade-offs
  • Time and space complexity analysis
  • Edge cases: empty tree, single node, skewed tree

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.