← Maven Clinic Interview Insights
I went with a greedy approach: iterate through the sorted list and fill each page slot with the next record whose payer_id isn't already on that page.
Start by clarifying requirements and constraints, then propose a greedy round-robin approach that cycles through payers to fill each page, ensuring diversity. Explain how to handle the edge case where one payer dominates by either allowing duplicates or adjusting page composition, and analyze time and space complexity.
Pro tip: Mention that since the list is pre-sorted, you can group records by payer in O(n) time, and then use a round-robin pointer to efficiently select records for each page. Also, discuss the trade-off between strict diversity and page size when a payer has too many records.
Ask about the definition of 'maximizing diversity', whether duplicates are allowed if unavoidable, and if the original order within a payer must be preserved. Confirm page size x and whether pages must be filled completely.
Since the list is sorted, group records by payer_id into a list of queues or arrays, each containing records for one payer. This takes O(n) time and O(n) space.
For each page, iterate through the payer groups in a round-robin fashion, taking one record from each payer until the page is full. Skip payers that have no remaining records. This ensures maximum diversity per page.
If a payer has more records than remaining slots on a page, after all other payers are exhausted, fill the remaining slots with records from that payer. This may result in duplicates on the page, but it's unavoidable. Alternatively, if strict diversity is required, leave slots empty or adjust page size.
Time complexity: O(n) for grouping + O(n) for round-robin selection = O(n). Space complexity: O(n) for storing groups. Discuss potential optimizations like using a min-heap to always pick from the payer with the most remaining records, but note that round-robin is simpler and sufficient.
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