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This is basically interval merging but across k sorted lists instead of one flat list.
Use a min-heap to merge intervals from k sorted lists, similar to merging k sorted arrays, but with interval merging logic. Pop the interval with the smallest start time, then merge it with the last interval in the result if they overlap; otherwise, append it. Push the next interval from the same camera into the heap, ensuring O(N log k) time where N is total intervals.
Pro tip: Clarify that intervals from the same camera are non-overlapping and sorted, so you only need to compare the current interval with the last merged interval; also mention that if intervals are inclusive/exclusive, adjust the overlap condition accordingly.
Restate the problem: merge intervals from k sorted lists into one sorted, non-overlapping list. Confirm that intervals are sorted and non-overlapping within each camera, and that N is total intervals.
Select a min-heap (priority queue) to efficiently retrieve the interval with the smallest start time across all cameras. Each heap entry stores the interval and the camera index (and possibly the index within that camera's list).
Push the first interval from each camera into the heap. While the heap is not empty, pop the smallest interval, merge it with the last interval in the result if they overlap, otherwise append it. Then push the next interval from the same camera if available.
Explain that each interval is pushed and popped once, and heap operations take O(log k), leading to O(N log k) time. Space is O(k) for the heap plus O(N) for the output.
Consider edge cases: empty input, intervals that touch (e.g., [1,2] and [2,3]), and intervals that are completely contained. Mention alternative approaches like divide-and-conquer or sweep line, and why heap is optimal here.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.