← Databricks Interview Insights
The key insight is that F(n) has F(n-1) nodes in the left subtree and F(n-2) in the right, so if you know the total size you can figure out the split point and recursively reconstruct.
First, clarify the definition of a Fibonacci tree and its recursive size property: a Fibonacci tree of order n has left subtree of order n-1 and right subtree of order n-2 (or vice versa), with sizes following Fibonacci numbers. Then, use the in-order sequence and the known subtree sizes to recursively locate the root and partition the sequence, reconstructing the tree. Finally, analyze the time and space complexity, noting the exponential growth of tree size with n.
Pro tip: Mention that the in-order traversal alone is insufficient without the Fibonacci property; explicitly state that the property provides the missing structural information. Also, note that the algorithm can be optimized to O(N) time by precomputing Fibonacci numbers and using indices, avoiding repeated size calculations.
Explain that a Fibonacci tree of order n is a binary tree where the left and right subtrees are Fibonacci trees of orders n-1 and n-2 (or vice versa), and its size is F_{n+2}-1 (or similar, depending on indexing). Clarify the recursive size relationship.
Given the total size N of the tree (derived from the length of the in-order sequence), find n such that the size matches a Fibonacci tree. Then, the root is at index size(left subtree) in the in-order sequence, where size(left) is the size of the left subtree (either F_{n+1}-1 or F_n-1).
Split the in-order sequence into left and right subsequences based on the root's position. Recursively apply the same process to each subsequence, using the appropriate Fibonacci orders for the subtrees.
Discuss that the tree size grows exponentially with n (N = Θ(φ^n)), so the algorithm takes O(N) time if implemented efficiently (e.g., with precomputed Fibonacci numbers and linear-time partitioning). Space complexity is O(N) for the tree and O(n) for recursion stack.
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