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Snowflake·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jul 2026

Summary

Snowflake SWE interview that was basically three connected problems about error detection and failure propagation. The sub-problem structure felt clever at first but by part C I was running on fumes.

Questions Asked (3)

Q1

You have a chronologically ordered log array where each line starts with '[Info]', '[Warn]', or '[Error]'. Once an '[Error]' appears, all subsequent lines are also errors, and there's at least one '[Warn]' right before the first error. Find the index of the first '[Error]' using as few reads as possible. What do you return if no error exists?

Algorithms & Data Structures
Author's notes

Binary search, obviously, but I fumbled explaining why the guarantees matter.

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AI HintsAI Generated

Suggested Approach

Recognize that the log array is sorted by error status: all non-errors come first, then all errors. Use binary search to find the first error in O(log n) reads. If no error exists, return -1 (or a sentinel like -1) to indicate absence.

Pro tip: Mention that the '[Warn]' right before the first error can serve as a validation check or be used to narrow the search, but binary search alone is optimal. Also, clarify the return value for no error upfront to avoid ambiguity.

1. Clarify the problem and constraints

Confirm that the array is sorted by error status (all non-errors then all errors) and that you need the index of the first error. Ask what to return if no error exists (e.g., -1).

2. Identify the binary search condition

Define the predicate: a line is an error if it starts with '[Error]'. The array is partitioned: false for non-errors, true for errors. Find the first true.

3. Implement binary search

Use two pointers (low, high) and repeatedly check the middle element. If it's an error, move high to mid; else move low to mid+1. Continue until low == high.

4. Handle edge cases

Check if the first element is an error (return 0) or if the last element is not an error (return -1). Also, consider empty array (return -1).

5. Return the result

After the loop, low is the index of the first error if it exists; otherwise, return -1. Optionally, verify with the '[Warn]' condition.

Key Points to Mention

  • Binary search reduces reads to O(log n), which is optimal for a sorted array.
  • The array is sorted by error status: all non-errors precede all errors.
  • The return value for no error should be -1 (or a sentinel) to indicate absence.
  • Edge cases: empty array, all errors, no errors, single element.
  • The '[Warn]' before the first error can be used as a sanity check but is not needed for the algorithm.
  • Time complexity: O(log n) reads; space complexity: O(1).

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given a directed service dependency graph where an edge U to V means U calls V, and given the ID of the first failing service, find all services that will eventually fail due to cascading upstream failures.

Algorithms & Data StructuresSystem Design
Author's notes

This one I actually liked.

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AI HintsAI Generated

Suggested Approach

Model the problem as a graph traversal starting from the first failing service, but traverse edges in the reverse direction (i.e., from V to U) to find all services that depend on it. Use BFS or DFS to collect all reachable nodes, ensuring you handle cycles and avoid revisiting nodes. Return the set of affected services.

Pro tip: Clarify whether the graph is static or dynamic, and discuss how to handle large-scale graphs efficiently (e.g., using iterative BFS to avoid stack overflow). Also, mention that in real systems, you might need to consider failure propagation delays or partial failures.

1. Understand the problem and clarify assumptions

Confirm that edges represent calls (U calls V), so failure propagates from V to U. Ask if the graph is directed, if there are cycles, and if all services fail immediately or with delay.

2. Choose the right traversal direction

Since we need upstream services that depend on the failing service, traverse the graph in reverse: from the failing service, follow incoming edges to find its callers.

3. Select and implement traversal algorithm

Use BFS or DFS to explore all reachable nodes in the reverse graph. Maintain a visited set to avoid infinite loops in cyclic graphs.

4. Collect and return results

Gather all visited nodes (excluding the initial failing service if desired) and return them as the set of services that will eventually fail.

5. Analyze complexity and edge cases

Discuss time and space complexity (O(V+E)), and consider edge cases like disconnected graphs, self-loops, or multiple failing services.

Key Points to Mention

  • Reverse graph traversal (following incoming edges) to find upstream dependencies
  • BFS vs DFS trade-offs: BFS for shortest path or level-order, DFS for simplicity; iterative vs recursive
  • Cycle handling using a visited set to prevent infinite loops
  • Time and space complexity: O(V+E) for traversal, O(V) for visited set
  • Real-world considerations: dynamic graphs, failure delays, partial failures, and scalability
  • Clarifying questions: directedness, cycles, multiple initial failures, and whether the failing service itself is included

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

Using the same graph and initial failing service, find one of the longest possible chains of cascading failures starting from that service. State your assumptions about cycles and justify them.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This is where things got messy.

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AI HintsAI Generated

Suggested Approach

Model the services as a directed graph where edges represent failure propagation, then find the longest simple path from the initial failing service using DFS with backtracking. Explicitly state that cycles are disallowed to prevent infinite loops and because a service failing once cannot fail again, and justify this assumption based on the problem's realistic constraints.

Pro tip: Mention that the problem is NP-hard in general, so for large graphs you'd need heuristics or approximations, but for interview purposes, assume a manageable graph size and focus on correctness and clear assumptions.

1. Clarify the graph and failure propagation

Confirm that the graph is directed, edges indicate that if the source fails, the target fails, and the initial failing service is given. Ask if multiple edges or self-loops exist.

2. State assumptions about cycles

Assume cycles are not allowed in the failure chain because a service can only fail once; thus, we seek the longest simple path. Justify that this prevents infinite loops and reflects real-world cascading failures.

3. Choose an algorithm

Use DFS with backtracking to explore all simple paths from the start node, keeping track of the longest path found. Alternatively, if the graph is a DAG, use dynamic programming for efficiency.

4. Implement and handle edge cases

Write pseudocode for the DFS, ensuring visited nodes are tracked to avoid cycles. Consider disconnected nodes, multiple longest paths, and the possibility that the start node has no outgoing edges.

5. Analyze complexity and trade-offs

Discuss time complexity (exponential in worst case) and space complexity (O(V) for recursion stack). Mention that for large graphs, approximation or heuristic methods may be needed.

Key Points to Mention

  • Directed graph representation and adjacency list
  • Longest simple path problem and its NP-hard nature
  • Cycle avoidance to prevent infinite loops and ensure realistic failure propagation
  • DFS with backtracking for path enumeration
  • Dynamic programming for DAGs as an optimization
  • Time and space complexity analysis

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.