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Netflix·Software Engineer·Technical Phone Screen·Senior

Senior
May 2026

Summary

Netflix SWE interview with a string pairs problem that pushed past brute force. The interviewer wanted a real algorithmic solution, not just the naive O(n^2 * L) approach, so you had to actually think about bitmask encoding and complement enumeration.

Questions Asked (1)

Q1

Given a list of n strings, find the number of unique unordered pairs (i, j) where i < j such that strings[i] and strings[j] share no common characters. The interviewer wanted a solution better than the naive O(n^2 * L) approach.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

I started with the brute force just to show I understood the problem, which I think was fine, but I could tell they were waiting for me to push further.

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AI HintsAI Generated

Suggested Approach

Start by clarifying constraints (n, L, alphabet size) and discussing the naive O(n^2 * L) approach. Then propose a bitmask-based solution: represent each string as a bitmask of characters, and for each string, count compatible strings using a frequency map of masks. Optimize by iterating over submasks of the complement or using SOS DP to achieve O(n + 2^A) where A is alphabet size.

Pro tip: Always discuss trade-offs: bitmask approach is fast for small alphabets (e.g., lowercase letters) but may be memory-heavy for large alphabets; consider hybrid approaches or pruning based on constraints. Also, mention that the interviewer likely wants to see how you handle ambiguity and optimize for the given constraints.

1. Clarify constraints and requirements

Ask about input size (n, L), alphabet size, and whether strings can be empty or contain duplicates. Confirm that pairs are unordered and i < j.

2. Discuss naive approach and its complexity

Explain the O(n^2 * L) solution: for each pair, check common characters by iterating through strings or using sets. This sets a baseline for optimization.

3. Propose bitmask representation

Convert each string to a bitmask where each bit represents a character's presence. This reduces character comparison to bitwise AND operations.

4. Optimize counting using frequency map and submask enumeration

Count frequencies of each mask. For each mask, find compatible masks by enumerating submasks of the complement (characters not present) and summing their frequencies. Alternatively, use SOS DP to precompute sums over subsets.

5. Analyze complexity and trade-offs

Compare O(n^2 * L) vs O(n + 2^A) where A is alphabet size. Discuss when each is preferable and potential memory usage.

Key Points to Mention

  • Bitmask representation of strings for efficient character set operations
  • Frequency map of masks to avoid redundant comparisons
  • Submask enumeration or SOS DP to count compatible strings in O(2^A) per mask
  • Time complexity: O(n * L + n * 2^A) or O(n + 2^A) with SOS DP, where A is alphabet size
  • Space complexity: O(2^A) for frequency array or map
  • Trade-offs: bitmask approach excels for small alphabets (e.g., 26 lowercase letters) but may be impractical for large alphabets; consider hybrid or pruning strategies

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.