Blanked for a second because I was expecting a coding problem.
First, recognize that the sum of logs equals the log of the product: log(1) + log(2) + log(3) + log(4) + log(5) = log(120). Then, since both sides are log(120), they are equal. Alternatively, compute the product 1*2*3*4*5 = 120 and compare directly.
Pro tip: Mention that this relies on the logarithmic identity log(a) + log(b) = log(ab), and note that the base of the logarithm doesn't matter as long as it's consistent. This shows you understand the underlying mathematical property and can generalize.
Recall that the sum of logarithms of numbers equals the logarithm of their product: log(a) + log(b) = log(ab).
Combine the sum on the right: log(1) + log(2) + log(3) + log(4) + log(5) = log(1*2*3*4*5).
Calculate 1*2*3*4*5 = 120. So the right side simplifies to log(120).
Both sides are log(120), so they are equal. Therefore, neither is greater; they are the same.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.