The median approach clicked pretty fast for me.
First, explain that the unconstrained Manhattan distance minimizer is the median of x-coordinates and median of y-coordinates. Then, if that point is blocked, search nearby cells (e.g., within a small radius) to find the optimal valid location. Finally, compute the total distance and return the minimum and one optimal location.
Pro tip: Mention that the optimal unconstrained point is the median, and if blocked, the next best is among the 4 neighbors or within a small neighborhood; this shows you understand the problem's structure and can optimize the search.
Compute the median of all house x-coordinates and the median of all house y-coordinates. This point minimizes the sum of Manhattan distances without any constraints.
If the median point is not a tree cell, it is the answer. If it is blocked, proceed to find the next best valid location.
If the median is blocked, evaluate candidate points near the median (e.g., all cells within a small radius, or the four adjacent cells) that are not trees. Compute the total distance for each and pick the minimum.
For the chosen valid location, calculate the sum of Manhattan distances to all houses. Return this minimum total distance and the location.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.