I knew frequency counting was the right move but fumbled the aggregation step.
Clarify that 'changing at most k characters' means you can replace characters in the first string to make it an anagram of the second. Use frequency counting: compute the difference in character counts between the two strings, and the minimum number of changes needed is the sum of positive differences (or half the sum of absolute differences). Compare this minimum to k.
Pro tip: Mention that the problem reduces to counting mismatched characters after accounting for duplicates, and note that the minimum changes equals the number of characters in the first string that are not matched in the second. This shows you understand the underlying combinatorial optimization.
Confirm that 'changing' means replacing a character in the first string, and that the goal is to make the first string an anagram of the second. Also confirm that strings are equal length and contain only lowercase English letters (or clarify character set).
Build frequency arrays or hash maps for both strings to count occurrences of each character.
For each character, if the count in the first string exceeds the count in the second, the excess must be changed. Sum these excesses to get the minimum number of changes required.
If the minimum changes needed is less than or equal to k, return true; otherwise, return false.
State that the time complexity is O(n) where n is the length of the strings, and space complexity is O(1) if using a fixed-size array for lowercase letters (or O(c) for character set size).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.