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Classic BST traversal problem but I always second-guess myself on the edge cases.
Start by clarifying the definition of in-order successor and the tree structure. Then explain the two cases: if the node has a right subtree, the successor is the leftmost node in that subtree; otherwise, it's the lowest ancestor for which the node is in its left subtree. Provide pseudocode and analyze time and space complexity.
Pro tip: Mention that without parent pointers, finding the successor requires a traversal from the root, but with parent pointers, it can be done in O(h) time without extra space. This shows awareness of practical variations.
Confirm the definition of in-order successor (next node in in-order traversal) and whether nodes have parent pointers. Also, discuss edge cases like the maximum node having no successor.
Describe the two cases: if the node has a right child, go right then leftmost; else, go up until you find a node that is a left child of its parent. If no such ancestor, successor is null.
Write clear pseudocode for both cases, handling the absence of parent pointers by keeping track of the ancestor during traversal from the root.
State that time complexity is O(h) where h is the tree height, and space complexity is O(1) if parent pointers exist, else O(h) for recursion or O(1) for iterative with ancestor tracking.
Walk through examples: a node with a right subtree, a leaf node that is a left child, a leaf that is a right child, and the maximum node.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.