My first instinct was greedy, which went nowhere fast.
Recognize that the end-to-end throughput is the minimum across services, so the goal is to raise the lowest service's throughput as high as possible within budget. Use binary search on the target throughput T, and for each T, compute the minimum cost to make every service's throughput at least T; if total cost ≤ budget, T is feasible. Then find the maximum feasible T.
Pro tip: Mention that scaling decisions are independent per service once T is fixed, and that the cost function is monotonic in T, enabling binary search. Also note that if a service's initial throughput already meets T, its cost is zero.
Restate the problem: N services in series, each with a current throughput, an increment per scaling step, and a cost per step. Budget B. Maximize the minimum throughput after scaling. Ask about constraints (N, budget, increments, costs) to determine feasible complexity.
Observe that if a target throughput T is achievable within budget, any T' < T is also achievable. This monotonicity allows binary search on T.
For a given T, compute for each service the minimum number of scaling steps needed to reach at least T: steps_i = max(0, ceil((T - current_i) / increment_i)). The cost for service i is steps_i * cost_i. Sum costs; if ≤ B, T is feasible.
Set low = min(current throughputs), high = min(current_i + (B / cost_i) * increment_i) or a safe upper bound. While low < high, mid = (low + high + 1) // 2; if feasible(mid), low = mid; else high = mid - 1. Return low.
Time: O(N log(maxT)) where maxT is the upper bound. Space: O(1). Discuss edge cases: budget insufficient to scale any service, services already above target, large numbers requiring 64-bit integers, and potential overflow in cost calculation.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.