My first instinct was greedy and it was wrong.
Model the problem as a dynamic programming problem where dp[i] represents the maximum score to reach index i. For each index i, consider transitions from i-1 (always allowed) and from any previous index j where arr[j] ends in 3 (if arr[i] ends in 3). Compute dp values in order and return dp[n-1].
Pro tip: Clarify that the score includes the value at the starting index (index 0) and the ending index, as this is a common ambiguity. Also, mention that if no valid path exists, the problem might be unsolvable, but typically a path exists via i+1 moves.
Restate the problem: start at index 0, end at last index, moves are to i+1 or to any j>i where arr[j] ends in 3. Score is sum of visited indices. Ask clarifying questions about edge cases (e.g., empty array, single element, negative numbers).
Let dp[i] be the maximum score to reach index i. Initialize dp[0] = arr[0]. For i>0, dp[i] = arr[i] + max(dp[i-1], max over j<i where arr[i] ends in 3 of dp[j]). If arr[i] does not end in 3, only consider dp[i-1].
To avoid O(n^2) time, maintain a variable max_dp_ending_in_3 that stores the maximum dp[j] for all j where arr[j] ends in 3. Update it as you compute dp[i]. This reduces time to O(n).
Check for empty array (return 0 or handle as per problem). For single element, return arr[0]. After computing dp, return dp[n-1]. Discuss potential integer overflow and use appropriate data types.
State time complexity O(n) and space complexity O(n) (or O(1) if optimized). Walk through a small example to verify correctness, including cases with negative numbers and multiple jumps.
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