← Akuna Capital Interview Insights
I knew prefix sums going in but the negative numbers justification tripped me up more than I expected.
Use a hash map to store the cumulative sum frequencies. Iterate through the array, updating the cumulative sum and checking if (cumulative sum - k) exists in the map. This counts all subarrays with sum k in O(n) time, and the map handles negative numbers naturally because it tracks all possible prefix sums.
Pro tip: Emphasize that the hash map approach works for negative numbers because it doesn't rely on monotonicity, unlike sliding window. Also, mention that you initialize the map with {0: 1} to account for subarrays starting from index 0.
Confirm that the array can contain negative numbers and that we need to count all contiguous subarrays. State that O(n) time and O(n) space are required.
Define prefix sum as the sum of elements from index 0 to i. A subarray from j+1 to i has sum k if prefix_sum[i] - prefix_sum[j] = k, i.e., prefix_sum[j] = prefix_sum[i] - k.
Initialize a hash map with {0: 1} to handle subarrays starting at index 0. Iterate through the array, update cumulative sum, and for each sum, add the frequency of (sum - k) to the count, then increment the frequency of the current sum.
Explain that the hash map approach works with negative numbers because it doesn't assume the prefix sums are increasing. It simply counts all pairs of indices where the difference in prefix sums equals k.
Time complexity is O(n) because we traverse the array once and each hash map operation is O(1) on average. Space complexity is O(n) for the hash map, which can store up to n distinct prefix sums.
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