Classic problem but I always second-guess myself on whether to transpose first or do the reverse.
Clarify the rotation direction (clockwise or counterclockwise) and confirm the matrix is square. The optimal in-place solution is to first transpose the matrix and then reverse each row (for clockwise rotation) or reverse each column (for counterclockwise). Explain the time and space complexity and handle edge cases like 1x1 or empty matrix.
Pro tip: Mention that the transpose-and-reverse method is equivalent to a 4-way swap of elements in cycles, but the former is simpler to implement and less error-prone. Also, discuss how the approach can be adapted for non-square matrices if needed.
Ask whether the rotation is clockwise or counterclockwise, and confirm the matrix is square (N x N). Also check if in-place is mandatory or if extra space is allowed.
Decide between the transpose-and-reverse method (simpler) or the layer-by-layer 4-way swap (more direct). Explain the trade-offs.
For clockwise rotation, swap matrix[i][j] with matrix[j][i] for all i < j. This transposes the matrix in place.
For clockwise, reverse each row; for counterclockwise, reverse each column. This completes the rotation.
State O(N^2) time and O(1) space. Test with 1x1, 2x2, and empty matrix. Mention that the method works for any N.
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