I went straight to building a row-to-list-of-(col, val) map for A and a similar structure for B.
First, clarify the sparse matrix representation (e.g., list of (row, col, value) or CSR) and the expected output format. Then describe an algorithm that iterates over non-zero entries of A and B, using a hash map or dense accumulator to compute only necessary dot products. Finally, derive the time complexity in terms of nnz(A) and nnz(B), discussing trade-offs between different multiplication orders.
Pro tip: Mention that for very sparse matrices, iterating over non-zero entries of A and for each, over non-zero entries of B in the same row can be more efficient than the standard row-by-column approach, and that using a hash map for the output avoids dense intermediate storage.
Ask whether the input matrices are given in a specific sparse format (e.g., list of triplets, CSR) and whether the output should be dense or sparse. Confirm the dimensions and that multiplication is valid (A's columns = B's rows).
Describe an algorithm that processes only non-zero entries. For example, for each non-zero A[i][k], iterate over non-zero B[k][j] and accumulate the product into a hash map keyed by (i,j). Alternatively, use CSR and iterate over rows.
Use a hash map or dictionary to store the output sparsely, avoiding a dense m x n matrix. If using CSR, leverage row pointers and column indices to efficiently access non-zeros.
Derive the complexity: O(nnz(A) * average non-zeros per row of B) or more precisely O(sum over non-zero A[i][k] of nnz(B[k][:])). Discuss best and worst cases, and compare to dense O(m*k*n).
Mention that the order of multiplication (A*B vs B*A) can affect efficiency, and that using a dense accumulator for rows with many non-zeros might be faster. Also note memory vs time trade-offs.
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