I recognized the meeting rooms problem pretty quickly but then stalled on what they actually wanted back.
Use a sweep line algorithm: create events for each meeting start (+1) and end (-1), sort them by time, then iterate through events while maintaining a running count of active rooms. At each distinct timestamp, record the count after processing all events at that time, ensuring that end events are processed before start events if intervals are half-open [start, end).
Pro tip: Clarify the interval semantics: since intervals are [start, end), a meeting ending at time t does not overlap with one starting at t, so process end events before start events at the same timestamp. Also, mention that this approach can be extended to find the maximum number of rooms needed.
Confirm that intervals are half-open [start, end), meaning a meeting ending at time t and another starting at t do not overlap. Ask whether the output should include timestamps with zero active meetings.
For each meeting, create two events: (start, +1) and (end, -1). Use a list or array to store these events.
Sort the events by time. If two events have the same time, process end events (-1) before start events (+1) to respect the half-open interval semantics.
Iterate through the sorted events, maintaining a running count of active rooms. At each distinct timestamp, after processing all events at that time, record the count.
Return the list of (timestamp, count) pairs or an array of counts for each unit time interval, depending on the requirement.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.