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Nextdoor·Machine Learning Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Did a coding round for an MLE role at Nextdoor. Just one question, a merge intervals variant, nothing too surprising if you've been grinding leetcode.

Questions Asked (1)

Q1

Given a list of intervals, merge all overlapping ones and return the result.

Algorithms & Data Structures
Author's notes

Pretty standard if you've seen it before.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem constraints (e.g., whether intervals are sorted, inclusive/exclusive endpoints, and expected output format). Then propose a sort-based approach: sort intervals by start time, iterate through them, and merge overlapping intervals by comparing the current interval's start with the previous merged interval's end. Finally, analyze time and space complexity and discuss edge cases.

Pro tip: Mention that sorting is the key to achieving O(n log n) time, and that without sorting, the problem would require O(n^2) comparisons. Also, proactively discuss how you would handle edge cases like empty input or intervals that touch at endpoints.

1. Clarify requirements and constraints

Ask about input format, whether intervals are sorted, endpoint inclusivity, and expected output. Confirm if intervals are given as pairs [start, end] and if merging touching intervals (e.g., [1,2] and [2,3]) is required.

2. Choose an efficient algorithm

Propose sorting intervals by start time, then merging in a single pass. Explain why this yields O(n log n) time due to sorting, and O(n) space for the output.

3. Walk through the merge logic

Describe iterating through sorted intervals: if the current interval's start <= last merged interval's end, update the end to max of both ends; otherwise, add the last merged interval to the result and start a new one.

4. Analyze complexity and edge cases

State time and space complexity. Discuss edge cases: empty list, single interval, all overlapping, none overlapping, and intervals with same start times.

5. Test with examples

Walk through a concrete example, such as [[1,3],[2,6],[8,10],[15,18]] -> [[1,6],[8,10],[15,18]], to verify correctness and demonstrate understanding.

Key Points to Mention

  • Sorting intervals by start time is crucial for O(n log n) efficiency.
  • Merge condition: current.start <= lastMerged.end (or < if endpoints are exclusive).
  • Update the end of the merged interval to the maximum of the two ends.
  • Time complexity: O(n log n) due to sorting; space complexity: O(n) for the output.
  • Edge cases: empty input, single interval, intervals that touch at endpoints, and unsorted input.
  • Alternative approaches (e.g., using a stack) and why sorting is preferred.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.